Category Archives: Class 10

NCERT Solutions For Class 10 Maths Chapter 2 Polynomials

Get Free NCERT Solutions for Class 10 Maths Chapter 2 Ex 2.1 PDF. Polynomials Class 10 Maths NCERT Solutions are extremely helpful while doing homework. Exercise 2.1 Class 10 Maths Polynomials NCERT Solutions were prepared by Experienced Teachers. Detailed answers of all the questions in Chapter 2 maths class 10 Polynomials Exercise 2.1 provided in NCERT TextBook.

Topics and Sub Topics in Class 10 Maths Chapter 2 Polynomials:

Section Name Topic Name
2 Polynomials
2.1 Introduction
2.2 Geometrical Meaning Of The Zeroes Of A Polynomial
2.3 Relationship Between Zeroes And Coefficients Of A Polynomial
2.4 Division Algorithm For Polynomials
2.5 Polynomials
2.6 Summary

NCERT Solutions For Class 10 Maths Chapter 2 Polynomials

NCERT Solutions for Class 10 Maths Chapter 2 Polynomials Ex 2.1 are part of NCERT Solutions for Class 10 Maths. Here we have given Maths NCERT Solutions Class 10 Chapter 2 Polynomials Exercise 2.1.

Board CBSE
Textbook NCERT
Class Class 10
Subject Maths
Chapter Chapter 2
Chapter Name Polynomials
Exercise Ex 2.1
Number of Questions Solved 1
Category NCERT Solutions

NCERT Solutions for Class 10 Maths Chapter 2 Polynomials Ex 2.1

Ex 2.1 Class 10 Maths Question 1:
The graphs of y = p(x) are given below for some polynomials p(x). Find the number of zeroes of p(x) in each case.
NCERT Solutions For Class 10 Maths Chapter 2 Polynomials Q1

NCERT Solutions For Class 10 Maths Chapter 2 Polynomials Q2

NCERT Solutions For Class 10 Maths Chapter 2 Polynomials Q3
Solution:
NCERT Solutions for Class 10 Maths Chapter 2 Polynomials Ex 2.1 Q1

You can also download the free PDF of Ex 2.1 Class 10 Polynomials NCERT Solutions or save the solution images and take the print out to keep it handy for your exam preparation.

NCERT Solutions for Class 10 Maths Chapter 2 Polynomial (Hindi Medium) Ex 2.1

NCERT Solutions for class 10 Maths Chapter 2 Exercise 2.1 Polynomials
NCERT Solutions for class 10 Maths Chapter 2 Exercise 2.1 Polynomials in hindi
NCERT Solutions for class 10 Maths Chapter 2 Exercise 2.1 in PDF form

Download PDF Now – Real Numbers Class 10 Maths NCERT Solutions

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Class 10 Maths NCERT Solutions Chapter 2 Polynomials

Polynomials Class 10 Maths NCERT Solutions

NCERT Solutions for Class 10 Maths Chapter 2 Polynomials are part of NCERT Solutions for Class 10 Maths. Here we have given Maths NCERT Solutions Class 10 Chapter 2 Polynomials.

Class 10 Maths NCERT Solutions Chapter 2 Polynomials Ex 2.1

Question 1:
The graphs of y = p(x) are given below for some polynomials p(x). Find the number of zeroes of p(x) in each case.
NCERT Solutions for Class 10 Maths Chapter 2 Polynomials Ex 2.1 Q1
Polynomials Ex 2.1 NCERT Solutions for Class 10 Maths Chapter 2
Polynomials Exercise 2.1 NCERT Solutions for Class 10 Maths Chapter 2
Solution:
NCERT Solutions for Class 10 Maths Chapter 2 Polynomials Ex 2.1 Q1

Class 10 Maths NCERT Solutions Chapter 2 Polynomials Ex 2.2

Question 1.
Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and their coefficients:
(i) x2 – 2x – 8
(ii) 4s2 – 4s + 1
(iii) 6x2 – 3 – 7x
(iv) 4u2 + 8u
(v) t2 – 15
(vi) 3x2 – x – 4
Solution:
NCERT Solutions for Class 10 Maths Chapter 2 Polynomials Ex 2.2 Q1

Question 2.
Find a quadratic polynomial each with the given numbers as the sum and product of zeroes respectively:
Polynomials Ex 2.2 NCERT Solutions for Class 10 Maths Q2
Solution:
Polynomials Class 10 Chapter 2 NCERT Solutions Ex 2.2 Q2

Class 10 Maths NCERT Solutions Chapter 2 Polynomials Ex 2.3

Question 1.
Divide the polynomial p(x) by the polynomial g(x) and find the quotient and remainder in each of the following:
(i) p(x) = x3 – 3x2 + 5x – 3, g(x) = x2 – 2
(ii) p(x) = x4 – 3x2 + 4x + 5, g(x) = x2 + 1 – x
(iii) p(x) = x4– 5x + 6, g(x) = 2 – x2
Solution:
NCERT Solutions for Class 10 Maths Chapter 2 Polynomials Ex 2.3 Q1

Question 2.
Check whether the first polynomial is a factor of the second polynomial by dividing the second polynomial by the first polynomial.
(i) t2 – 3, 2t4 + 3t3 – 2t2– 9t – 12
(ii) x2 + 3x + 1, 3x4 + 5x3 – 7x2 + 2x + 2
(iii) x2 + 3x + 1, x5 – 4x+ x2 + 3x + 1
Solution:
Polynomials class 10 Ex 2.3 Maths NCERT Solutions Q2
Question 3.
Obtain all other zeroes of 3x4 + 6x3 – 2x2 – 10x – 5, if two of its zeroes are  and (sqrt { frac { 5 }{ 3 } }) and –(sqrt { frac { 5 }{ 3 } })
Solution:
Polynomials Class 10 Chapter 2 Maths NCERT Solutions Ex 2.3 Q3
Question 4.
On dividing x– 3x2 + x + 2bya polynomial g(x), the quotient and remainder were x – 2 and -2x + 4 respectively. Find g(x).
Solution:
Polynomials NCERT Solutions for Class 10 Maths Chapter 2 Ex 2.3 Q4
Question 5.
Give examples of polynomials p(x), g(x), q(x) and r(x), which satisfy the division algorithm and:
(i) deg p(x) = deg q(x)
(ii) deg q(x) = deg r(x)
(iii) deg r(x) = 0
Solution:
Polynomials Class 10 Maths NCERT Solutions Chapter 2 Ex 2.3 Q5

Class 10 Maths NCERT Solutions Chapter 2 Polynomials Ex 2.4

Question 1.
Verify that the numbers given alongside of the cubic polynomials below are their zeroes. Also, verify the relationship between the zeroes and the coefficients in each case:
(i) 2x3 + x2 – 5x + 2;  (frac { 1 }{ 4 }), 1, -2
(ii) x3 – 4x2 + 5x – 2; 2, 1, 1
Solution:
NCERT Solutions for Class 10 Maths Chapter 2 Polynomials Ex 2.4 Q1
Question 2.
Find a cubic polynomial with the sum, some of the product of its zeroes taken two at a time, and the product of its zeroes as 2, -7, -14 respectively.
Solution:
Polynomials Class 10 Maths NCERT Solutions Chapter 2 Ex 2.4 Q2
Question 3.
If the zeroes of the polynomial x3 – 3x2 + x + 1 are a-b, a, a + b, find a and b.
Solution:
Polynomials Class 10 Maths NCERT Solutions Exercise 2.4 Q3
Question 4.
If two zeroes of the polynomial x4 – 6x3 – 26x2 + 138x – 35 are 2 ± √3, find other zeroes.
Solution:
Polynomials Exercise 2.4 Class 10 Maths NCERT Solutions Q4
Question 5.
If the polynomial x4 – 6x3 + 16x2 – 25x + 10 is divided by another polynomial x2 – 2x + k, the remainder comes out to be x + a, find k and a.
Solution:
Polynomials Ex 2.4 Class 10 Maths NCERT Solutions Q4

Class 10 Maths Polynomials Mind Map

Polynomial

An algebraic expression f(x) of the form
f(x) = a0 + a1x + a2x2 +…. + anxn,
where a0, a1, ……., an are real numbers and all indices of variables are non-negative integers is called polynomial in variable x.
(i) The highest power of x is called degree of the polynomial.
(ii) a0, a1x,….,anxn are terms of the polynomial.
(iii) a0, a1 ,….an are co-efficients of the polynomial.

Class 10 Maths NCERT Solutions Chapter 2 Polynomials 1

Standard Forms of Linear, Quadratic and Cubic Polynomials

(i) Linear Polynomial:
ax + b, where a, b are real numbers and a ≠ 0.
(ii) Quadratic Polynomial:
ax2 + bx + c, where a, b, c are real numbers & a ≠ 0.
(iii) Cubic Polynomials:
ax3 + bx2 + cx + d, where a, b, c, d are real numbers and a ≠ 0.

Value of a Polynomial

The value of a polynomial f(x) at x = a is obtained by substituting x = a in the given polynomial and is denoted by/(a).

Zero(es)/Root(s) of Polynomial

x = r is a zero of a polynomial p(x) if p(r) = 0.

Geometrical Meaning of Zeroes of a Polynomial

Class 10 Maths NCERT Solutions Chapter 2 Polynomials 2
Zero(es) of a polynomial is/are the x-coordinate of the point(s) where graph y = fix) intersects the x-axis.
(i) Linear polynomial: Graph of linear polynomial is a straight line and has exactly one zero.
(ii) Quadratic polynomial: Graph of quadratic polynomial is always a parabola and this polynomial can have atmost two zeroes.
(iii) Cubic polynomial: Cubic polynomial can have atmost three zeroes.

Cases of Quadratic Polynomial

Case-I : If a quadratic polynomial P(x) = ax2 + bx + c has two zeroes, then its graph will intersect the x-axis at two distinct points A and B as shown in the figure.
Class 10 Maths NCERT Solutions Chapter 2 Polynomials 3
Case-II: If a quadratic polynomial P(x) = ax2 + bx + c has only one zero, then its graph will touch the x-axis at only one point A as shown in the figure.
Class 10 Maths NCERT Solutions Chapter 2 Polynomials 4
Case-III : If a quadratic polynomial P(x) = ax2 + bx + c has no zero, then its graph will not intersect /touch the x-axis at any point as shown in the figure.
Class 10 Maths NCERT Solutions Chapter 2 Polynomials 5

Relationship between Zeroes and Coefficients of a Polynomial
(i) Zero of a linear polynomial ax + b is x = (-frac{b}{a})
(ii) If α and β are the zeroes of the quadratic polynomial ax2 + bx + c, then
α + β = (-frac{b}{a})
Class 10 Maths NCERT Solutions Chapter 2 Polynomials 6
(iii) If α, β and γ are zeroes of the cubic polynomial ax3 + bx2 + cx + d then
Class 10 Maths NCERT Solutions Chapter 2 Polynomials 7

Division Algorithm

If p(x) and g(x) are any two polynomials with g(x) ≠ 0, then we can find polynomials q(x) and r(x) such that p(x) = g(x) × q(x) + r(x)
where either r(x) = 0 or degree of r(x) < degree of g(x)

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NCERT Solutions for Class 10 Sanskrit Shemushi भाग 2 | शेमुषी संस्कृत Class 10 Solutions

NCERT Solutions for Class 10 Sanskrit Shemushi: Detailed, Step-by-Step NCERT Solutions for Class 10 Sanskrit Shemushi शेमुषी भाग 2 Text Book Questions and Answers solved by Expert Teachers as per NCERT (CBSE) Book guidelines. Download Now.

Sanskrit Class 10 NCERT Solutions | Shemushi संस्कृत कक्षा 10 समाधान

Shemushi Sanskrit Class 10 Solutions

Here is the list of Class 10 Sanskrit Chapters.

  1. NCERT Solutions for Class 10 Sanskrit Chapter 1 शुचिपर्यावरणम्
  2. Shemushi Sanskrit Class 10 Solutions Chapter 2 बुद्धिर्बलवती सदा
  3. Sanskrit Class 10 NCERT Solutions Chapter 3 व्यायामः सर्वदा पथ्यः
  4. Class 10 Sanskrit Solutions Chapter 4 शिशुलालनम्
  5. Class 10th Sanskrit Book Solutions Chapter 5 जननी तुल्यवत्सला
  6. 10th Class Sanskrit Book Solution Chapter 6 सुभाषितानि
  7. Shemushi Sanskrit Class 10 Solutions Chapter 7 सौहार्दं प्रकृतेः शोभा
  8. NCERT Class 10 Sanskrit Solutions Chapter 8 विचित्रः साक्षी
  9. Shemushi Class 10 Solutions Chapter 9 सूक्तयः
  10. Shemushi संस्कृत कक्षा 10 समाधान Chapter 10 भूकंपविभीषिका
  11. शेमुषी संस्कृत Class 10 Solutions Chapter 11 प्राणेभ्योऽपि प्रियः सुह्रद्
  12. शेमुषी भाग 2 Solutions Chapter 12 अनयोक्त्यः

Abhyasvan Bhav Sanskrit Class 10 Solutions

Abhyasvan Bhav Sanskrit Class 10 Solutions अभ्यासवान् भव भाग 2

NCERT Class 10 Sanskrit Grammar Book Solutions

Sanskrit Class 10 Grammar | Sanskrit Grammar Book for Class 10 CBSE Pdf

खण्डः ‘क’ (अपठित-अवबोधनम्)

खण्डः ‘ख’ (रचनात्मक कार्यम्)

खण्डः ‘ग’ (अनुप्रयुक्त-व्याकरणम्)

NCERT Solutions for Class 10 Sanskrit
NCERT Solutions for Class 10 Sanskrit

NCERT Solutions for Class 10 Sanskrit Shemushi

  1. NCERT Solutions for Class 10 Sanskrit Chapter 1 शुचिपर्यावरणम्
  2. Shemushi Sanskrit Class 10 Solutions Chapter 2 बुद्धिर्बलवती सदा
  3. Sanskrit Class 10 NCERT Solutions Chapter 3 व्यायामः सर्वदा पथ्यः
  4. Class 10 Sanskrit Solutions Chapter 4 शिशुलालनम्
  5. Class 10th Sanskrit Book Solutions Chapter 5 जननी तुल्यवत्सला
  6. 10th Class Sanskrit Book Solution Chapter 6 सुभाषितानि
  7. Shemushi Sanskrit Class 10 Solutions Chapter 7 सौहार्दं प्रकृतेः शोभा
  8. NCERT Class 10 Sanskrit Solutions Chapter 8 विचित्रः साक्षी
  9. Shemushi Class 10 Solutions Chapter 9 सूक्तयः
  10. Shemushi संस्कृत कक्षा 10 समाधान Chapter 10 भूकंपविभीषिका
  11. शेमुषी संस्कृत Class 10 Solutions Chapter 11 प्राणेभ्योऽपि प्रियः सुह्रद्
  12. शेमुषी भाग 2 Solutions Chapter 12 अनयोक्त्यः

Abhyasvan Bhav Sanskrit Class 10 Solutions

Abhyasvan Bhav Sanskrit Class 10 Solutions अभ्यासवान् भव भाग 2

NCERT Class 10 Sanskrit Grammar Book Solutions

Sanskrit Class 10 Grammar | Sanskrit Grammar Book for Class 10 CBSE Pdf

खण्डः ‘क’ (अपठित-अवबोधनम्)

खण्डः ‘ख’ (रचनात्मक कार्यम्)

खण्डः ‘ग’ (अनुप्रयुक्त-व्याकरणम्)

More Resources for CBSE Class 10

NCERT Solutions for Class 10 English Literature Reader

NCERT Solutions for Class 10 English Literature Reader are the part of NCERT Solutions for Class 10 English. Here we have given NCERT Solutions for Class 10 English Literature Reader.

NCERT Solutions for Class 10 English Literature Reader

NCERT Solutions for Class 10 English Literature Reader

Fiction

Poetry

Drama

We hope the given NCERT Solutions for Class 10 English Literature Reader will help you. If you have any query regarding NCERT Solutions for Class 10 English Literature Reader, drop a comment below and we will get back to you at the earliest.

MCQ Questions for Class 10 Maths Arithmetic Progressions with Answers

Free PDF Download of CBSE Class 10 Maths Chapter 5 Arithmetic Progressions Multiple Choice Questions with Answers. MCQ Questions for Class 10 Maths with Answers was Prepared Based on Latest Exam Pattern. Students can solve NCERT Class 10 Maths Arithmetic ProgressionsMCQs with Answers to know their preparation level.

Class 10 Maths MCQs Chapter 5 Arithmetic Progressions

1. The nth term of an A.P. is given by an = 3 + 4n. The common difference is
(a) 7
(b) 3
(c) 4
(d) 1

Answer/Explanation

Answer: c
Explaination:Reason: We have an = 3 + 4n
∴ an+1 = 3 + 4(n + 1) = 7 + 4n
∴ d = an+1 – an
= (7 + 4n) – (3 + 4n)
= 7 – 3
= 4


2. If p, q, r and s are in A.P. then r – q is
(a) s – p
(b) s – q
(c) s – r
(d) none of these

Answer/Explanation

Answer: c
Explaination:Reason: Since p, q, r, s are in A.P.
∴ (q – p) = (r – q) = (s – r) = d (common difference)


3. If the sum of three numbers in an A.P. is 9 and their product is 24, then numbers are
(a) 2, 4, 6
(b) 1, 5, 3
(c) 2, 8, 4
(d) 2, 3, 4

Answer/Explanation

Answer: d
Explaination:Reason: Let three numbers be a – d, a, a + d
∴ a – d +a + a + d = 9
⇒ 3a = 9
⇒ a = 3
Also (a – d) . a . (a + d) = 24
⇒ (3 -d) .3(3 + d) = 24
⇒ 9 – d² = 8
⇒ d² = 9 – 8 = 1
∴ d = ± 1
Hence numbers are 2, 3, 4 or 4, 3, 2


4. The (n – 1)th term of an A.P. is given by 7,12,17, 22,… is
(a) 5n + 2
(b) 5n + 3
(c) 5n – 5
(d) 5n – 3

Answer/Explanation

Answer: d
Explaination:Reason: Here a = 7, d = 12-7 = 5
∴ an-1 = a + [(n – 1) – l]d = 7 + [(n – 1) -1] (5) = 7 + (n – 2)5 = 7 + 5n – 10 = 5M – 3


5. The nth term of an A.P. 5, 2, -1, -4, -7 … is
(a) 2n + 5
(b) 2n – 5
(c) 8 – 3n
(d) 3n – 8

Answer/Explanation

Answer: c
Explaination:Reason: Here a = 5, d = 2 – 5 = -3
an = a + (n – 1)d = 5 + (n – 1) (-3) = 5 – 3n + 3 = 8 – 3n


6. The 10th term from the end of the A.P. -5, -10, -15,…, -1000 is
(a) -955
(b) -945
(c) -950
(d) -965

Answer/Explanation

Answer: a
Explaination:Reason: Here l = -1000, d = -10 – (-5) = -10 + 5 = – 5
∴ 10th term from the end = l – (n – 1 )d = -1000 – (10 – 1) (-5) = -1000 + 45 = -955


7. Find the sum of 12 terms of an A.P. whose nth term is given by an = 3n + 4
(a) 262
(b) 272
(c) 282
(d) 292

Answer/Explanation

Answer: a
Explaination:Reason: Here an = 3n + 4
∴ a1 = 7, a2 – 10, a3 = 13
∴ a= 7, d = 10 – 7 = 3
∴ S12 = (frac{12}{2})[2 × 7 + (12 – 1) ×3] = 6[14 + 33] = 6 × 47 = 282


8. The sum of all two digit odd numbers is
(a) 2575
(b) 2475
(c) 2524
(d) 2425

Answer/Explanation

Answer: b
Explaination:Reason: All two digit odd numbers are 11,13,15,… 99, which are in A.P.
Since there are 90 two digit numbers of which 45 numbers are odd and 45 numbers are even
∴ Sum = (frac{45}{2})[11 + 99] = (frac{45}{2}) × 110 = 45 × 55 = 2475


9. The sum of first n odd natural numbers is
(a) 2n²
(b) 2n + 1
(c) 2n – 1
(d) n²

Answer/Explanation

Answer: d
Explaination:Reason: Required Sum = 1 + 3 + 5 + … + upto n terms.
Here a = 1, d = 3 – 1 = 2
Sum = (frac{n}{2})[2 × 1 + (n – 1) × 2] = (frac{n}{2})[2 + 2n – 2] = (frac{n}{2}) × 2n = n²Reason: All two digit odd numbers are 11,13,15,… 99, which are in A.P.
Since there are 90 two digit numbers of which 45 numbers are odd and 45 numbers are even
∴ Sum = (frac{45}{2})[11 + 99] = (frac{45}{2}) × 110 = 45 × 55 = 2475


10. If (p + q)th term of an A.P. is m and (p – q)tn term is n, then pth term is
MCQ Questions for Class 10 Maths Arithmetic Progressions with Answers 1

Answer/Explanation

Answer: d
Explaination:Reason: Let a is first term and d is common difference
∴ ap + q = m
ap – q = n
⇒ a + (p + q – 1)d = m = …(i)
⇒ a + (p – q – 1)d = m = …(ii)
On adding (i) and (if), we get
2a + (2p – 2)d = m + n
⇒ a + (p -1)d = (frac{m+n}{2}) …[Dividing by 2
∴ an = (frac{m+n}{2})


11. If a, b, c are in A.P. then (frac{a-b}{b-c}) is equal to
MCQ Questions for Class 10 Maths Arithmetic Progressions with Answers 2

Answer/Explanation

Answer: a
Explaination:Reason: Since a, b, c are in A.P.
∴ b – a = c – b
⇒ (frac{b-a}{c-b}) = 1
⇒ (frac{a-b}{b-c}) = 1


12. The number of multiples lie between n and n² which are divisible by n is
(a) n + 1
(b) n
(c) n – 1
(d) n – 2

Answer/Explanation

Answer: d
Explaination:Reason: Multiples of n from 1 to n² are n × 1, n × 2, n × 3, …, m× n
∴ There are n numbers
Thus, the number of mutiples of n which lie between n and n² is (n – 2) leaving first and last in the given list: Total numbers are (n – 2).


13. If a, b, c, d, e are in A.P., then the value of a – 4b + 6c – 4d + e is
(a) 0
(b) 1
(c) -1.
(d) 2

Answer/Explanation

Answer: a
Explaination:Reason: Let common difference of A.P. be x
∴ b = a + x, c = a + 2x, d = a + 3x and e = a + 4x
Given equation n-4b + 6c-4d + c
= a – 4(a + x) + 6(A + 2r) – 4(n + 3x) + (o + 4.v)
= a – 4a – 4x + 6a + 12x – 4a – 12x + a + 4x = 8a – 8a + 16x – 16x = 0


14. The next term of the sequence
MCQ Questions for Class 10 Maths Arithmetic Progressions with Answers 3

Answer/Explanation

Answer: a
Explaination:
MCQ Questions for Class 10 Maths Arithmetic Progressions with Answers 4


15. nth term of the sequence a, a + d, a + 2d,… is
(a) a + nd
(b) a – (n – 1)d
(c) a + (n – 1)d
(d) n + nd

Answer/Explanation

Answer: a
Explaination:Reason: an = a + (n – 1)d


16. The 10th term from the end of the A.P. 4, 9,14, …, 254 is
(a) 209
(b) 205
(c) 214
(d) 213

Answer/Explanation

Answer: a
Explaination:Reason: Here l – 254, d = 9-4 = 5
∴ 10th term from the end = l – (10 – 1 )d = 254 -9d = 254 = 9(5) = 254 – 45 = 209


17. If 2x, x + 10, 3x + 2 are in A.P., then x is equal to
(a) 0
(b) 2
(c) 4
(d) 6

Answer/Explanation

Answer: d
Explaination:Reason: Since 2x, x + 10 and 3x + 2 are in A.P.
∴ 2(x + 10) = 2x + (3x + 2)
⇒ 2x + 20 – 5x + 2
⇒ 2x – 5x = 2 – 20
⇒ 3x = 18
⇒ x = 6


18. The sum of all odd integers between 2 and 100 divisible by 3 is
(a) 17
(b) 867
(c) 876
(d) 786

Answer/Explanation

Answer: b
Explaination:Reason: The numbers are 3, 9,15, 21, …, 99
Here a = 3, d = 6 and an = 99
∴ an = a + (n – 1 )d
⇒ 99 = 3 + (n – 1) x 6
⇒ 99 = 3 + 6n – 6
⇒ 6n = 102
⇒ n = 17
Required Sum = (frac{n}{2})[a + an] = (frac{17}{2})[3 + 99] = (frac{17}{2}) × 102 = 867


19. If the numbers a, b, c, d, e form an A.P., then the value of a – 4b + 6c – 4d + e is
(a) 0
(b) 1
(c) -1
(d) 2

Answer/Explanation

Answer: a
Explaination:Reason: Let x be the common difference of the given AP
∴ b = a + x, c = a + 2x, d = a + 3x and e = a + 4x
∴ a – 4b + 6c – 4d + e = a – 4 (a + x) + 6(a + 2x) – 4(a + 3x) + (a + 4x)
= a – 4a – 4x + 6a + 12x – 4a – 12x + a + 4x = 8a – 8a + 16x – 16x = 0


20. If 7 times the 7th term of an A.P. is equal to 11 times its 11th term, then 18th term is
(a) 18
(b) 9
(c) 77
(d) 0

Answer/Explanation

Answer: d
Explaination:Reason: We have 7a7 = 11a11
⇒ 7[a + (7 – 1)d] = 11[a + (11 – 1 )d]
⇒ 7(a + 6d) = 11(a + 10d)
⇒ 7a + 42d = 11a + 110d
⇒ 4a = -68d
⇒ a = -17d
∴ a18 = a + (18 – 1)d = a + 17d = -17d + 17d = 0


We hope the given MCQ Questions for Class 10 Maths Arithmetic Progressions with Answers will help you. If you have any query regarding CBSE Class 10 Maths Chapter 5 Arithmetic Progressions Multiple Choice Questions with Answers, drop a comment below and we will get back to you at the earliest.

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Polynomials Class 10 Extra Questions Maths Chapter 2

Polynomials Class 10 Extra Questions Maths Chapter 2

Extra Questions for Class 10 Maths Chapter 2 Polynomials. According to new CBSE Exam Pattern, MCQ Questions for Class 10 Maths Carries 20 Marks.

Polynomials Class 10 Extra Questions Maths Chapter 2 Q1

You can also download Maths NCERT Solutions Class 10 to help you to revise complete syllabus and score more marks in your examinations.

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Polynomials Class 10 Extra Questions Maths Chapter 2 Q8

Polynomials Class 10 Extra Questions Maths Chapter 2 Q9

Polynomials Class 10 Extra Questions Maths Chapter 2 Q10

Polynomials Class 10 Extra Questions Maths Chapter 2 Q11

Polynomials Class 10 Extra Questions Maths Chapter 2 Q12

Polynomials Class 10 Extra Questions Maths Chapter 2 Q13

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Polynomials Class 10 Extra Questions Maths Chapter 2 Q17

Polynomials Class 10 Extra Questions Maths Chapter 2 Q18

Polynomials Class 10 Extra Questions Maths Chapter 2 Q19

Polynomials Class 10 Extra Questions Maths Chapter 2 Q20

Polynomials Class 10 Extra Questions Maths Chapter 2 Q21

Polynomials Class 10 Extra Questions Maths Chapter 2 Q22

Extra Questions for Class 10 Maths

NCERT Solutions for Class 10 Maths

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NCERT Solutions For Class 10 Maths Chapter 2 Polynomials Ex 2.4

Get Free NCERT Solutions for Class 10 Maths Chapter 2 Ex 2.4 PDF. Polynomials Class 10 Maths NCERT Solutions are extremely helpful while doing homework. Exercise 2.4 Class 10 Maths NCERT Solutions were prepared by Experienced Teachers. Detailed answers of all the questions in Chapter 2 maths class 10 Polynomials Exercise 2.4 provided in NCERT TextBook.

Topics and Sub Topics in Class 10 Maths Chapter 2 Polynomials:

Section Name Topic Name
2 Polynomials
2.1 Introduction
2.2 Geometrical Meaning Of The Zeroes Of A Polynomial
2.3 Relationship Between Zeroes And Coefficients Of A Polynomial
2.4 Division Algorithm For Polynomials
2.5 Polynomials
2.6 Summary

You can also download the free PDF of  Ex 2.4 Class 10 Polynomials NCERT Solutions or save the solution images and take the print out to keep it handy for your exam preparation.

Board CBSE
Textbook NCERT
Class Class 10
Subject Maths
Chapter Chapter 2
Chapter Name Polynomials
Exercise Ex 2.4
Number of Questions Solved 5
Category NCERT Solutions

NCERT Solutions For Class 10 Maths Chapter 2 Ex 2.4

NCERT Solutions for Class 10 Maths Chapter 2 Polynomials Ex 2.4 are part of NCERT Solutions for Class 10 Maths. Here we have given Maths NCERT Solutions Class 10 Chapter 2 Polynomials Exercise 2.4.
Ex 2.4 Class 10 Maths Question 1.
Verify that the numbers given alongside of the cubic polynomials below are their zeroes. Also, verify the relationship between the zeroes and the coefficients in each case:
(i) 2x3 + x2 – 5x + 2;  (frac { 1 }{ 4 }), 1, -2
(ii) x3 – 4x2 + 5x – 2; 2, 1, 1
Solution:
NCERT Solutions for Class 10 Maths Chapter 2 Polynomials Ex 2.4 Q1

Ex 2.4 Class 10 Maths Question 2.
Find a cubic polynomial with the sum, some of the product of its zeroes taken two at a time, and the product of its zeroes as 2, -7, -14 respectively.
Solution:
Polynomials Class 10 Maths NCERT Solutions Chapter 2 Ex 2.4 Q2
Ex 2.4 Class 10 Maths Question 3.
If the zeroes of the polynomial x3 – 3x2 + x + 1 are a-b, a, a + b, find a and b.
Solution:
Polynomials Class 10 Maths NCERT Solutions Exercise 2.4 Q3
Ex 2.4 Class 10 Maths Question 4.
If two zeroes of the polynomial x4 – 6x3 – 26x2 + 138x – 35 are 2 ± √3, find other zeroes.
Solution:
Polynomials Exercise 2.4 Class 10 Maths NCERT Solutions Q4
Ex 2.4 Class 10 Maths Question 5.
If the polynomial x4 – 6x3 + 16x2 – 25x + 10 is divided by another polynomial x2 – 2x + k, the remainder comes out to be x + a, find k and a.
Solution:
Polynomials Ex 2.4 Class 10 Maths NCERT Solutions Q4

NCERT Solutions for Class 10 Maths Chapter 2 Polynomial (Hindi Medium) Ex 2.4

Class 10 Maths chapter 2 exercise 2.4 solutions in Hindi Medium

We hope the NCERT Solutions for Class 10 Maths Chapter 2 Polynomials Ex 2.4, help you. If you have any query regarding Maths NCERT Solutions Chapter 2 Polynomials Exercise 2.4, drop a comment below and we will get back to you at the earliest.

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Introduction to Trigonometry Class 10 Extra Questions Maths Chapter 8

Introduction to Trigonometry Class 10 Extra Questions Maths Chapter 8

Extra Questions for Class 10 Maths Chapter 8 Introduction to Trigonometry. According to new CBSE Exam Pattern, MCQ Questions for Class 10 Maths Carries 20 Marks.

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You can also download Class 10 Maths to help you to revise complete syllabus and score more marks in your examinations.

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Extra Questions for Class 10 Maths

NCERT Solutions for Class 10 Maths

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Extra Questions for Class 10 Maths Triangles

Triangles Class 10 Extra Questions Maths Chapter 6

Extra Questions for Class 10 Maths Chapter 6 Triangles. According to new CBSE Exam Pattern, MCQ Questions for Class 10 Maths Carries 20 Marks.

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You can also download NCERT Solutions Class 10 Maths to help you to revise complete syllabus and score more marks in your examinations.

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Extra Questions for Class 10 Maths

NCERT Solutions for Class 10 Maths

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NCERT Solutions for Class 10 English

NCERT Solutions for Class 10 English – In this article we have included all the details regarding NCERT Solutions for Class 10 English. Working on CBSE Class 10 NCERT Solutions for class 10 English will help candidates to build a strong foundation over the subject English.

It is necessary that every student should have a strong command over the language as English plays a major role in every student’s life. Also, English is considered to scoring subject in class 10. So, the students who wish to make a good grade in class 10, can work on the subject English to ace the exam with colorful grades.

In this article, we will provide you with all the necessary information regarding NCERT Solutions for Class 10 English. Read on to find out everything about NCERT Solutions for class 10 English literature and course book.

Class 10 English NCERT Solutions

NCERT Solutions for Class 10 Communicative English

NCERT Solutions for Class 10 English Literature Reader

Fiction

Poetry

Drama

NCERT Solutions for Class 10 English Language and Literature

NCERT Solutions for Class 10 English First Flight

NCERT Solutions for Class 10 English
NCERT Solutions for Class 10 English

NCERT Solutions for Class 10 English First Flight (Prose)

NCERT Solutions for Class 10 English First Flight (Poem)

NCERT Solutions for Class 10 English Footprints Without Feet

NCERT Solutions for Class 10 English Supplementary Reader Footprints without Feet

NCERT Solutions for Class 10 English Extended Reading Text / Novels / Long Reading Text

CBSE Class 10 English Main Course Book Solutions and Answers

CBSE Class 10 English Main Course Book MCB Solutions and Answers

Unit 1 Health and Medicine

Unit 2 Education

Unit 3 Science

Unit 4 Environment

Unit 5 Travel and Tourism 

Unit 6 National Integration

CBSE Class 10 English Workbook Solutions and Answers

NCERT Solutions for Class 10 English Workbook

CBSE Class 10 English Reading

CBSE Class 10 English Writing

CBSE Class 10 English Grammar

A. Resource Material

B. Integrated Grammar

For More Resources

NCERT Solutions for Class 10 English Literature (Download PDF)

Preparation Articles

More Resources for CBSE Class 10

FAQs on NCERT Solutions for Class 10 English

1. Which is the best guide for English for Class 10 CBSE?

NCERT Solutions for Class 10 English Literature can ace up the exam preparation. You can have a strong command over the English Language with NCERT Solutions.

2. How can I study well for English Class 10?

Make use of the preparation resources like Study Material, Books, NCERT Solutions for Class 10 to score better grades in the board exams.

3. How should I revise for the Class 10 English Board Examination?

Practice as much as you can with the quick links available on page for CBSE Class 10 English Literature Board Exams. Chapterwise Solutions organized under each topic makes it easy for you to crack the exam with better grades.

4. What are the best ways to prepare for the Class 10th English Board Exam (CBSE)?

Try solving previous papers of Class 10 English Board Exams. Refer to the NCERT Solutions for Class 10 English Literature existing here as a reference if you are stuck at some point during your preparation.

5. How can I improve my marks in English in Class 10 Board?

The secret to good marks lies in some factors like being clear in grammar, correct composition. Learn the correct format for reports or letters. Last not but least your handwriting does affect your marks. So, allot time and pay attention to your handwriting.

6. From where can I download NCERT Class 10 English Literature Solutions Chapterwise?

You can get the NCERT Class 10 English Literature Solutions Chapterwise organized under the Parent Topics from our site . Try practicing as much as you can with the NCERT Solutions over here to score well.

We hope the given NCERT Solutions for Class 10 English will help you. If you have any query regarding CBSE English NCERT Solutions Class 10, drop a comment below and we will get back to you at the earliest.