NCERT Solutions For Class 6 Maths Fractions Exercise 7.4

Free download NCERT Solutions for Class 6 Maths Chapter 7 Ex 7.4 Fractions PDF for CBSE 2020 Exams.

You can also Download NCERT Solutions for Class 6 Maths to help you to revise complete Syllabus and score more marks in your examinations.

• Fractions Class 6 Ex 7.1
• Fractions Class 6 Ex 7.2
• Fractions Class 6 Ex 7.3
• Fractions Class 6 Ex 7.4
• Fractions Class 6 Ex 7.5
• Fractions Class 6 Ex 7.6

NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.4

Exercise 7.4

Question 1.
Write shaded portion as fraction. Arrange them in ascending and descending order using correct sign ‘<‘, ‘=’, ‘>’ between the fractions.

(c) Show (frac { 2 }{ 4 }) , (frac { 4 }{ 6 }) , (frac { 8 }{ 6 }) and (frac { 6 }{ 6 }) on the number line. Put appropriate signs between the fractions given.

Solution:
(a) Total number of divisions = 8
(i) Number of shaded parts = 3
∴ Fraction = (frac { 3 }{ 8 })

(ii) Total number of divisions = 8
Number of shaded parts = 6
∴ Fraction = (frac { 6 }{ 8 })

(iii) Total number of divisions = 8
Number of shaded parts = 4
∴ Fraction = (frac { 4 }{ 8 })

(iv) Total number of divisions = 8
Number of shaded part = 1
∴ Fraction = (frac { 1 }{ 8 })
Now the fractions are:
(frac { 3 }{ 8 }), (frac { 6 }{ 8 }), (frac { 4 }{ 8 }) and (frac { 1 }{ 8 }) with same denominator.

(b)(i) Total number of divisions = 9
Number of shaded parts = 8
∴ Fraction = (frac { 8 }{ 9 })
(ii) Total number of divisions = 9
Number of shaded parts = 4
∴ Fraction = (frac { 4 }{ 9 })
(iii) Total number of divisions = 9
Number of shaded parts = 3
∴ Fraction = (frac { 3 }{ 9 })
(iv) Total number of divisions = 9
Number of shaded parts = 6
∴ Fraction = (frac { 6 }{ 9 })
∴ Fractions are (frac { 8 }{ 9 }), (frac { 4 }{ 9 }), (frac { 3 }{ 9 }), (frac { 6 }{ 9 }) with same denominator.

Question 2.
Compare the fractions and put an appropriate sign.

Solution:

Here, denominators of the two fractions are same and 3 < 5.

Here, numerators of the fractions are same and 7 > 4.

Here, denominators of the two fractions are same and 4 < 5.

Here, numerators of the two fractions are same and 5 < 7.

Question 3.
Make five more such pairs and put appropriate signs.
Solution:

Question 4.
Look at the figures and write ’<’, or ’>’ ’=’ between the given pairs of fractions.

Make five more such problems and solve them with your friends
Solution:

Make five more such problems yourself and solve them with your friends.

Question 5.
How quickly can you do this? Fill appropriate sign. ‘<‘, ‘=’, ‘>’.


Solution:



Question 6.
The following fractions represent just three different numbers. Separate them into three groups of equivalent fractions, by changing each one to its simplest form.

Solution:

Now grouping the above fractions into equivalent fractions, we have

Question 7.
Find answers to the following. Write and indicate how you solved them.

Solution:

By cross-multiplying, we get
5 x 5 = 25 and 4 x 9 = 36
Since 25 ≠ 36

By cross-multiplying, we get
9 x 9 = 81 and 16 x 5 =80
Since 81 ≠ 80

By cross-multiplying, we get
4 x 20 = 80 and 5 x 16 = 80
Since 80 = 80

By cross-multiplying, we get
1 x 30 = 30 and 4 x 15 = 60

Question 8.
Ila read 25 pages of a book containing 100 pages.
Lalita read (frac { 2 }{ 5 }) of the same book. Who read less?
Solution:
Ila reads 25 pages out of 100 pages.

Lalita reads (frac { 2 }{ 5 }) of the same book.
Comparing (frac { 1 }{ 4 }) and (frac { 2 }{ 5 }) , we get
1 x 5 = 5 and 2 x 4 = 8
Since 5 < 8
∴ (frac { 1 }{ 4 }) < (frac { 2 }{ 5 })
Hence Ila reads less pages.

Question 9.
Rafiq exercised for (frac { 3 }{ 6 }) of an hour, while Rohit exercised for (frac { 3 }{ 4 }) of an hour. Who exercised for a longer time?
Solution:
Rafiq exercised for (frac { 3 }{ 6 }) of an hour.
Rohit exercised for (frac { 3 }{ 4 }) of an hour.
Comparing (frac { 3 }{ 6 }) and (frac { 3 }{ 4 }) , we get
3 x 4 = 12 and 3 x 6 = 18
Since 12 < 18
∴ (frac { 3 }{ 4 }) > (frac { 3 }{ 6 })
Hence Rohit exercised for longer time.

Question 10.
In a class A of 25 students, 20 passed in first class, in another class B of 30 students, 24 passed in first class. In which class was a greater fraction of students getting first class?
Solution:
In class A, 20 students passed in first class out of 25 students.
∴ Fraction of students getting first class

In class B, 24 students passed in first class out of 30 students.
∴ Fraction of students getting first class

Comparing the two fractions, we get (frac { 4 }{ 5 }) = (frac { 4 }{ 5 })
Hence, both the class A and B have the same fractions.

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